Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

Using mass (M), length(L), time(T) and electric current (A) as fundamental quantities, the dimensions of permittivity will be : 

Options:

[MLT-1A-1]

[MLT-2A-2]

[M-1L-3T4A2]

[M2L-2T-2A]

Correct Answer:

[M-1L-3T4A2]

Explanation:

By Coulomb's Law : F = \(\frac{1}{4 \pi \epsilon_o} \frac{q_1 q_2}{r^2}\)

\(\epsilon_o = \frac{q_1 q_2}{4 \pi F r^2}\)

\([\epsilon_o] = \frac{[(AT)(AT)]}{[MLT^{-2}L^2]}\)

\([\epsilon_o] = [M^{-1}L^{-3}T^4A^2] \)