Using mass (M), length(L), time(T) and electric current (A) as fundamental quantities, the dimensions of permittivity will be :
Answer & explanation
Correct answer: option 3
By Coulomb's Law : F = \(\frac{1}{4 \pi \epsilon_o} \frac{q_1 q_2}{r^2}\)
\(\epsilon_o = \frac{q_1 q_2}{4 \pi F r^2}\)
\([\epsilon_o] = \frac{[(AT)(AT)]}{[MLT^{-2}L^2]}\)
\([\epsilon_o] = [M^{-1}L^{-3}T^4A^2] \)