Two coils have a mutual inductance of 0.005 H. The current changes in the first coil according to the equation $I = I_0sinωt,$ where $I_0 = 10 A$ and $ω = 100 \pi rad/s$. The maximum value of emf in the second coil is :
Answer & explanation
Correct answer: option 2
The correct answer is option (2) : $5\pi $
emf induced in the second coil $(\epsilon_s)$
$\epsilon_s=-L\frac{di_f}{dt}$
$⇒|\epsilon_s|=L\frac{di_s}{dt}$
$=L\frac{d}{dt}(I_0sin \omega t)$
$=L I_0\omega cos \omega t$
$⇒|\epsilon_s|_{max}=LI_0\omega $
$= 5\pi $