One number is selected at random from first two hundred positive integers. The probability that it is divisible by 6 or 8, is equal to
Answer & explanation
Correct answer: option 1
Total number of integers that are divisible by six
$\frac{200}{6}+\frac{200}{36}=38$
Total number of integers that are divisible by eight
$\frac{200}{8}+\frac{200}{64}=28$
Total number of integers that are divisible by six as well as by eight i.e. by 24
$\frac{200}{24}=8$
Thus total number of integers that are divisible by 6 or 8
= 38 + 28 – 8 = 58
Thus, required probability = $\frac{58}{200}=\frac{29}{100}$