One number is selected at random from first two hundred positive integers. The probability that it is divisible by 6 or 8, is equal to

$\frac{29}{100}$

Total number of integers that are divisible by six

$\frac{200}{6}+\frac{200}{36}=38$

Total number of integers that are divisible by eight

$\frac{200}{8}+\frac{200}{64}=28$

Total number of integers that are divisible by six as well as by eight i.e. by 24

$\frac{200}{24}=8$

Thus total number of integers that are divisible by 6 or 8

= 38 + 28 – 8 = 58

Thus, required probability = $\frac{58}{200}=\frac{29}{100}$