Practicing Success
A father's age is one year more than 5 times of his son's age. After 3 years, the father's age would be 2 years less than four times the son's age. Find the present age of the father. |
30 31 40 29 |
31 |
At present : ⇒ F = 5 S + 1 ..................(i) After 3 years: ⇒ F + 3 = 4 (S + 3) - 2 ⇒ F = 4 S + 12 - 5 ⇒ 5 S + 1 = 4 S + 7 (from (i)) ⇒ S = 6 ⇒ Therefore, age of Father = 5 S + 1 = (5 × 6) + 1 = 31 years |