[ 1 + \(\frac{cot^2A}{1 + cosec A}\)] [ \(\frac{tan^2 A}{sec A - 1}\) - 1] = ?
Answer & explanation
Correct answer: option 4
[ 1 + \(\frac{(cosec A -1) (1 + cosec A)}{(1 + cosec A)}\)] [ \(\frac{(sec A - 1)(sec A+1)}{(sec A- 1)}\) - 1]
= cosec A × sec A
= 2cosec2A