Practicing Success
[ 1 + \(\frac{cot^2A}{1 + cosec A}\)] [ \(\frac{tan^2 A}{sec A - 1}\) - 1] = ? |
2cos2A 2sin2A 2tan2A 2cosec2A |
2cosec2A |
[ 1 + \(\frac{(cosec A -1) (1 + cosec A)}{(1 + cosec A)}\)] [ \(\frac{(sec A - 1)(sec A+1)}{(sec A- 1)}\) - 1] = cosec A × sec A = 2cosec2A |