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In a ΔABC right angled at B, if BC= 4 cm and ∠C = 60°, then length of AB is: |
$4\sqrt{3}$cm $\frac{8}{\sqrt{3}}$cm 6 cm 8 cm |
$4\sqrt{3}$cm |
In triangle ABC , tan C = \(\frac{AB}{BC}\) According to question , tan 60º = √3 Now, √3 = \(\frac{AB}{4}\) AB = 4√3 |
