A 11 m long ladder is placed against a wall. It is inclined at an angle of 30° to the ground. The distance (in m) of the foot of the ladder from the wall is (Given √3 = 1.732)?
Answer & explanation
Correct answer: option 3
AC = ladder
θ = angle of inclination
BC = distance of foot from wall
cos θ= \(\frac{BC}{AC}\) ⇒ cos 30° = \(\frac{BC}{11}\)
⇒ \(\frac{\sqrt {3}}{2}\) = \(\frac{BC}{11}\)
⇒ \(\frac{11 × 1.732}{2}\) = BC
BC = 9.526m