CUET Preparation Today
For the LR circuit shown in figure, the phase angle if frequency is $100/π$ is
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30° 60° 45° 90° |
45° |
$X_L = \omega L = 2\pi \times \frac{100}{\pi} = 5 \Omega $ R = 5 $\Omega$ Phase angle $tan\theta = \frac{\omega L}{R}$ = 1 $\Rightarrow \theta = \frac{\pi}{4}$ |
