For the LR circuit shown in figure, the phase angle if frequency is $100/π$ is
Answer & explanation
Correct answer: option 3
$X_L = \omega L = 2\pi \times \frac{100}{\pi} = 5 \Omega $
R = 5 $\Omega$
Phase angle $tan\theta = \frac{\omega L}{R}$ = 1
$\Rightarrow \theta = \frac{\pi}{4}$