Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

What is the approximate wavelength of the radiation emitted when the electron in an hydrogen atom jumps from n = ∞ to n = 3 ?

Options:

822 Å

822 nm

8220 nm

365 nm

Correct Answer:

822 nm

Explanation:

$ \frac{1}{\lambda} = R(\frac{1}{3^2} - \frac{1}{\infty^2}) = \frac{R}{9}$

$\Rightarrow \lambda = \frac{9}{R} \approx 8220A^o = 822 nm $