If in a triangle ABC as drawn in the figure, AB = BC and ∠ACD = 130o, then ∠BAC is equal to :

Answer & explanation
Correct answer: option 2
Concept Used
Linear Pair theorem
Angle sum property = Sum of all the angles of the triangle is 130o
Calculation
In triangle ABC,
∠ACD + ∠ACB = 180o (Linear pair)
∠ACB = 180 - 130 = 50o
Since AB = BC,
Triangle ABC is an isosceles triangle.
∠ACB = ∠BAC = 50o
Therefore,∠BAC is 50o.