In a basket there are seven different fruits M, N, O, P, Q, R and S, each having a different weight. P is the heaviest. The weight of S is more than Q but less than O. The weight of M is the third lowest. R has the least weight. The weight of N is less than Q. How many fruits have more weight than S?
Answer & explanation
Correct answer: option 1
M, N, O, P, Q, R and S
1) P is the heaviest
2) R has the least weight
3) The weight of M is the third lowest
So, P>_ >_ >_ > M>_ >_ > R
4) The weight of S is more than Q but less than D
5) The weight of N is less than Q
So, P> O> S> Q> M> N> R
Therefore, Two(P&O) fruits have more weight than S