Practicing Success
Practicing Success
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The area of the figure bounded by the curves y = |x – 1| and y = 3 – |x| is |
2 3 4 None of these |
4 |
Required area $=\int\limits_{-1}^0 3+x-(-x+1) d x+\int\limits_0^1 3-x-(-x+1) d x+\int\limits_1^2 3-x-(x-1) d x$ $=\int\limits_{-1}^0(2+2 x) d x+\int\limits_0^1 2 d x+\int\limits_1^2(4-2 x) d x$ = 4 sq. units. Hence (3) is the correct answer. |
