If $ X + \frac{1}{2x}= 3,$ then evaluate $8x^3 +\frac{1}{x^3}$.
Answer & explanation
Correct answer: option 3
If $ X + \frac{1}{2x}= 3,$
Then, $8x^3 +\frac{1}{x^3}$ = ?
Multiply the equation with 2 = 2 ($ X + \frac{1}{2x}= 3,$)
=$ 2X + \frac{1}{x}= 6,$
$8x^3 +\frac{1}{x^3}$ = 63 - 3 × 6 × 2 = 180