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Home/Practice questions/Chemistry
ChemistryPhysical: Electro Chemistry

Identify the electrode and the element which undergoes oxidation in t…

Daniell Cell

Electrochemistry is the study of the production of electricity from energy released during spontaneous chemical reactions and the use of electrical energy to bring about non-spontaneous chemical transformations. The cell below represents Daniell cell which converts the chemical energy liberated during the redox reaction to electrical energy.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

The reaction is a combination of two half-cell reactions, one called the oxidation half-cell and the other called the reduction half-cell. Each half-cell consists of a metallic electrode dipped into an electrolyte. The two half-cells are connected through a metallic wire and switch externally. The electrolyte of the two half cells is connected internally through a salt bridge. At each electrode-electrolyte interface there is a tendency for metal ions from the solution to deposit on the metal electrode, trying to make it positively charged. At the same time, metal atoms of the electrode have a tendency to go into the solution as ions and leave behind the electrons at the electrode, trying to make it negatively charged. A potential difference develops between the electrode and the electrolyte, which is called electrode potential. When the concentrations of all the species involved in a half-cell is unity, then the electrode potential is known as the standard electrode potential.

For a general half-cell; Mn+(aq) + ne− → M(s), the Nernst equation is written as

\( E_{(M^{n+}/M)}=E^{o}_{(M^{n+}/M)}-\frac{RT}{nF}\ln\frac{1}{[M^{n+}]} \)

where \( E^{o}_{(M^{n+}/M)} \) is the standard reduction potential of the half-cell, R is gas constant (8.314 J K−1 mol−1), F is Faraday constant (96487 C mol−1), T is temperature in kelvin and [Mn+] is the concentration of the species, Mn+.

Identify the electrode and the element which undergoes oxidation in the Daniell cell?

Answer & explanation+

Correct answer: option 2

The correct answer is Option (2) → Anode, Zinc

In every electrochemical cell, oxidation takes place at the anode and reduction at the cathode. In a galvanic cell, the metal with the lower (more negative) standard reduction potential loses electrons and acts as the anode.

    \( \displaystyle E^{o}_{(\ce{Zn^2+}/\ce{Zn})}=-0.76\ \mathrm{V}\quad\quad E^{o}_{(\ce{Cu^2+}/\ce{Cu})}=+0.34\ \mathrm{V} \)

In the Daniell cell, zinc has the lower potential, so zinc atoms are oxidised at the zinc electrode, while \( \ce{Cu^{2+}} \) ions are reduced at the copper electrode:

    \( \displaystyle \text{Anode:}\quad \ce{Zn(s) -> Zn^2+(aq) + 2e^-} \)

    \( \displaystyle \text{Cathode:}\quad \ce{Cu^2+(aq) + 2e^- -> Cu(s)} \)

So the element that undergoes oxidation is zinc, and the electrode is the anode.

Why the other options are incorrect

  • Option (1) Anode, Copper — Incorrect. Copper is the cathode of the Daniell cell; copper is not oxidised here.

  • Option (3) Cathode, Copper — Incorrect. The copper electrode is the cathode, but reduction of \( \ce{Cu^{2+}} \), not oxidation, takes place there.

  • Option (4) Cathode, Zinc — Incorrect. Zinc is oxidised, but oxidation never takes place at the cathode.

NCERT (2026-27 edition):
Electrochemical Cells – “We had studied the construction and functioning of Daniell cell …. This cell converts the chemical energy liberated during the redox reaction

    \( \ce{Zn(s) + Cu^2+(aq) -> Zn^2+(aq) + Cu(s)} \qquad (2.1) \)

to electrical energy and has an electrical potential equal to 1.1 V when concentration of Zn2+ and Cu2+ ions is unity (1 mol dm–3). Such a device is called a galvanic or a voltaic cell.”

Textbook figure

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