Answer & explanation
Correct answer: option 1
$\text{Induced current }I = \frac{1}{R} \frac{d\phi}{dt} $
$ \text{Change in Flux } \Delta \phi = IR\Delta t = R \times Area under graph = 0.2\times 10 = 2 webers$
Correct answer: option 1
$\text{Induced current }I = \frac{1}{R} \frac{d\phi}{dt} $
$ \text{Change in Flux } \Delta \phi = IR\Delta t = R \times Area under graph = 0.2\times 10 = 2 webers$