A potential difference of 5 V is applied across a conductor of length 0.1 m. If the drift velocity of the electrons is 2.5 x 10-4 m s-1, calculate the electron mobility.

2.5 x 10-5 m2 V-1 s-1 5 x 10-5 m2 V-1 s-1 2.5 x 10-6 m2 V-1 s-1 5 x 10-6 m2 V-1 s-1

5 x 10-6 m2 V-1 s-1

Electric field : E = \(\frac{V}{l}\) Mobility μ = \(\frac{v_{d}}{E}\) = \(\frac{lv_{d}}{V}\) vd = 2.5 x 10-4 m s-1 ; l = 0.1 m ; V = 5 V  μ = 5 x 10-6 m2 V-1 s-1