Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Let x be the mean proportional between 25.6 and 32.4 and y be the third proportional to 32 and 48. Then 3x : 2y = ____.

Options:

5 : 3

3 : 5

4 : 5

5 : 4

Correct Answer:

3 : 5

Explanation:

Mean proportional (X) = \(\sqrt {25.6 x 32.4 }\)

⇒ X = 28.8

Third proportional (Y) = 32 : 48 : Y

⇒ 32Y = 48 x 48

⇒ 32Y = 2304

⇒ Y = 72,

3x : 2y = 3(28.8) : 2(72) = 86.4 : 144 = 3 : 5