The angle of elevation of the sun, when the length of the shadow of a tower is $1/\sqrt{3}$ times the height of the tower, is

60°

The correct answer is Option (3) → 60°

Let the height of the tower = h
Length of shadow = $\frac{1}{\sqrt{3}} h$

Step 1: Use tangent formula

$\tan \theta = \frac{\text{height}}{\text{shadow length}} = \frac{h}{\frac{h}{\sqrt{3}}} = \sqrt{3}$

Step 2: Find angle

$\tan \theta = \sqrt{3} ⇒\theta = 60^\circ$