In the given figure, AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF. If the angle at C is 34° , the angle ∠ADB is :

32° 17° 34° 16°

17°

We know that, If AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF, then ∠ADB = (1/2) ∠ACB We have, ∠ACB = 34° Now, According to the question ∠ADB = \(\frac{1}{2}\)  × 34° ∠ADB = 17°