CUET Preparation Today
The potential at points B and C, and the value of resistance R are
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10 V, 4 V, 4 $\Omega$ 6 V, 4 V, 5 $\Omega$ 10 V, 4 V, 6 $\Omega$ 6 V, 4 V, 4 $\Omega$ |
10 V, 4 V, 6 $\Omega$ |
The correct answer is Option (3) → 10 V, 4 V, 6 $\Omega$
let the potential at point A, B, C and D be $V_A,V_B,V_C$ and $V_D$ respectively. $V_B-V_A=10V$ $V_C-V_D=1×4=4V$ [By ohm's law] $V_B-V_C=10-4=6V$ $R=\frac{6}{1}=6Ω$ |
