CUET Preparation Today
CUET
-- Mathematics - Section B2
Calculus
General solution of $\frac{dy}{dx}+\sqrt{\frac{1-y^2}{1-x^2}}=0$ is :
$sin^{-1}x+sin^{-1}y=c$
$sin^{-1}x-sin^{-1}y=c$
$\frac{sin^{-1}x}{cos^{-1}x}=c$
$sin^{-1}xcos^{-1}y=c$
