Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

General solution of $\frac{dy}{dx}+\sqrt{\frac{1-y^2}{1-x^2}}=0$ is :

Options:

$sin^{-1}x+sin^{-1}y=c$

$sin^{-1}x+sin^{-1}y=c$

$\frac{sin^{-1}x}{cos^{-1}x}=c$

$sin^{-1}xcos^{-1}y=c$

Correct Answer:

$sin^{-1}x+sin^{-1}y=c$