Nitration of aniline with nitric acid and sulphuric acid gives major product as

p-nitroaniline

The correct answer is Option (2) → p-nitroaniline

While direct nitration of aniline in a strongly acidic medium yields a significant amount of the meta isomer, p-nitroaniline is still the major product by percentage yield.

Direct nitration of aniline using a mixture of concentrated nitric acid ($HNO_3$) and sulphuric acid ($H_2SO_4$) results in a mixture of three products with the following approximate yields at 288 K:

p-nitroaniline (51%): Despite the acidic medium, a portion of aniline remains unprotonated. The -NH2 group is a strong activator and directs the nitro group to the para position.

m-nitroaniline (47%): In the strong acid, the amino group gets protonated to form the anilinium ion (-NH3+), which is a deactivating and meta-directing group.

o-nitroaniline(2%): This is the minor product due to significant steric hindrance at the ortho position.

Option wise

1. m-nitroaniline: While it is formed in a surprisingly high amount (47%), it is the second-most abundant product, not the major one (51%).

3.o-nitroaniline: This is the minor product (only 2%) due to significant steric hindrance at the ortho position from the amino/anilinium group.

4.anilinium hydrogen sulphate: This is an intermediate salt formed when aniline reacts with cold concentrated sulfuric acid, but it is not the final product of a nitration reaction involving nitric acid.