Practicing Success
Ten capacitors each of 2 μF capacity were arranged in two rows such that first row contains 6 capacitors in series where as the rest were in second row. The equivalent capacitance of the network is: |
$\frac{5}{6}μF$ $20μF$ $\frac{24}{5}μF$ $\frac{6}{5}μF$ |
$\frac{5}{6}μF$ |
The correct answer is Option (1) → $\frac{5}{6}μF$ |