If the angle between the polarizer and the analyser is increased from 30 degrees to 60 degrees, how will the intensity vary ?
Answer & explanation
Correct answer: option 3
By I = Io Cos2\(\theta \) ,
$I_1 = I_0 \frac{3}{4}$
$I_2 = I_0 \frac{1}{4} = \frac{I_1}{3}$