Match List-I with List-II
Choose the correct answer from the options given below: |
A-I, B-II, C-III, D-IV A-IV, B-III, C-II, D-I A-I, B-II, C-IV, D-III A-II, B-III, C-I, D-IV |
A-I, B-II, C-IV, D-III |
The correct answer is: (1) A-I, B-II, C-III, D-IV Here is a brief explanation of each match: (A) \(C_6H_5CHO\): \(C_6H_5CHO\) (benzaldehyde) reacts with 2,4-dinitrophenylhydrazine (2,4-DNP) to form a yellow precipitate of 2,4-dinitrophenylhydrazone. This reaction is commonly used to identify carbonyl compounds. (B) \(CH_3C≡CH\): \(CH_3C≡CH\) (propene) reacts with ammoniacal silver nitrate to form a white precipitate of silver acetylide. This reaction is known as the Tollen's test and is used to distinguish between alkenes and alkynes. (C) \(HCN\): \(HCN\) (hydrogen cyanide) is a nucleophile. This means that it is attracted to and reacts with electropositive atoms or centers. HCN can react with a variety of organic compounds, including carbonyl compounds, to form new products. (D) \(I^-\): \(I^-\) (iodide ion) can react with carbonyl compounds to form cyanohydrins. This reaction is known as the haloform reaction. Cyanohydrins are useful intermediates in the synthesis of a variety of organic compounds. Therefore, the correct match is: (A) \(C_6H_5CHO\) - Precipitation with 2,4-DNP (B) \(CH_3C≡CH\) - Precipitation with AgNO3 (Ammonical) (C) \(HCN\) - Nucleophile (D) \(I^-\) - Cyanohydrin formation The correct answer is: (3) A-I, B-II, C-IV, D-III Here is a brief explanation of each match: (A) \(C_6H_5CHO\): \(C_6H_5CHO\) (benzaldehyde) reacts with 2,4-dinitrophenylhydrazine (2,4-DNP) to form a yellow precipitate of 2,4-dinitrophenylhydrazone. This reaction is commonly used to identify carbonyl compounds. (B) \(CH_3C=CH\): \(CH_3C=CH\) (propene) reacts with ammoniacal silver nitrate to form a white precipitate of silver acetylide. This reaction is known as the Tollen's test and is used to distinguish between alkenes and alkynes. (C) \(HCN\): \(HCN\) (hydrogen cyanide) is a nucleophile. This means that it is attracted to and reacts with electropositive atoms or centers. HCN can react with a variety of organic compounds, including carbonyl compounds, to form new products. (D) \(I^-\): \(I^-\) (iodide ion) can react with carbonyl compounds to form cyanohydrins. This reaction is known as the haloform reaction. Cyanohydrins are useful intermediates in the synthesis of a variety of organic compounds. Therefore, the correct match is: (A) \(C_6H_5CHO\) - Precipitation with 2,4-DNP (B) \(CH_3C=CH\) - Precipitation with AgNO3 (Ammonical) (C) \(HCN\) - Nucleophile (D) \(I^-\) - Cyanohydrin formation |