A conducting sphere of radius R is given a charge Q. What is the electric field and the electric potential at the centre of the sphere? |
$\frac{Q}{4πε_0R^2}$ and $\frac{Q}{4πε_0R}$ $\frac{Q}{4πε_0R^2}$ and zero zero and $\frac{Q}{4πε_0R}$ Both electric field and electric potential are zero |
zero and $\frac{Q}{4πε_0R}$ |
The correct answer is Option (2) → zero and $\frac{Q}{4πε_0R}$ As all the charge would get distributed on the surface. The net charge inside sphere is zero. and, As this sphere is an equipotential surface, $\frac{Q}{4πε_0R}$ at the center of sphere. |