Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

If 5% of the energy supplied to a bulb is irradiated as visible light, how many quanta are emitted per second by a 100 W lamp? (Assume wavelength of visible light as $5.6×10^{-5}cm$)

Options:

$1.4×10^{19}$

$3×10^3$

$1.4×10^{-19}$

$3×10^4$

Correct Answer:

$1.4×10^{19}$

Explanation:

Energy radiated as visible light = $\frac{5}{100}×100=5J/s$

Let n be the number of photons emitted per second. Then,

nhv = E = 5

$∴n=\frac{5λ}{hc}=\frac{5×5.6×10^{-7}}{(6.62×10^{-34})(3×10^8)}=1.4×10^{19}$