If cos θ=9/13, then what is the value of cosecθ ?

cosθ = \(\frac{9}{13}\)

{ using,  cosθ = \(\frac{B}{H}\) }

By using pythagoras theorem,

P² + B² = H²

P² + 9² = 13²

P² = 169 - 81 = 88

P = 4 \(\sqrt {22 }\)

Now,

cosec θ = \(\frac{13}{2√22}\)

= \(\frac{13√22}{44}\)