If $cos θ=\frac{9}{13}$, then what is the   value of cosecθ ?

$\frac{13}{\sqrt{22}}$ $\frac{13\sqrt{22}}{44}$ $\frac{2\sqrt{22}}{13}$ $\frac{\sqrt{22}}{13}$

$\frac{13\sqrt{22}}{44}$

cosθ = \(\frac{9}{13}\) { using,  cosθ = \(\frac{B}{H}\) } By using pythagoras theorem, P² + B² = H² P² + 9² = 13² P² = 169 - 81 = 88 P = 4 \(\sqrt {22 }\) Now, cosec θ = \(\frac{13}{2√22}\) = \(\frac{13√22}{44}\)