What is the least number of square tiles required to pave the floor of a room 15m and 17cm long and 9m and 2cm broad?

814

15m &17cm = 1517cm

9m &02cm = 902cm

Now,

HCF of 1517 & 902 = 41 = side of a square tile

No. of tiles (required) = \(\frac{area\;of\;floor}{area\;of\;1\;tile}\)

                                  = \(\frac{1517 × 902}{41 × 41}\) = 814