Target Exam

CUET

Subject

Section B1

Chapter

Matrices

Question:

Find the matrix $A^2$, where $A = [a_{ij}]$ is a $2 \times 2$ matrix whose elements are given by $a_{ij} = \text{maximum}(i, j) - \text{minimum}(i, j)$

Options:

$\begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}$

$\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}$

$\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$

$\begin{bmatrix} 1 & 1 \\ 1 & 1 \end{bmatrix}$

Correct Answer:

$\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$

Explanation:

The correct answer is Option (3) → $\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$ ##

Given for matrix $A=[a_{ij}]_{2 \times 2}$

We have, $a_{ij} = \text{maximum}(i, j) - \text{minimum}(i, j)$

$a_{11} = 1 - 1 = 0$

$a_{12} = 2 - 1 = 1$

$a_{21} = 2 - 1 = 1$

$a_{22} = 2 - 2 = 0$

$A = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}$

$A^2 = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$