The price of diesel increased by 16%. A person wants to increase his expenditure on diesel by 10% only. By what percentage, correct to one decimal place, should he reduce his consumption?
Answer & explanation
Correct answer: option 2
16% = \(\frac{4}{25}\)
10% = \(\frac{1}{10}\)
ATQ ,
Price 25 : 29
Consumption a : b
Expenditure 10 : 11
{ Price × Consumption = Expenditure }
Now ,
\(\frac{25a}{29b}\) = \(\frac{10}{11}\)
\(\frac{a}{b}\) = \(\frac{290}{275}\)
Consumption decreases by = 290 - 275 = 15
Decreased percentage = \(\frac{15}{290}\) × 100 = 5.17%
= 5.2%