At present the sum of the ages of A, B, C is 93 years, where as 10 years ago, the ratio of their age was 4 : 3 : 2. Find the present age of A, B and C.
Answer & explanation
Correct answer: option 2
Sum of age of A, B and C before 10 years = 93 - (3 × 10) = 63
⇒ 10 years ago ratio of age: A , B and C = 4 : 3 : 2 ⇒ 9R
here,
⇒ 9R = 63
⇒ 1R = 7
Therefore,
⇒ 10 yeas age age of A, B and C = 28, 21 and 14
⇒ Present age of A, B and C = (28 + 10), (21 + 10) and (14 + 10) = 38, 31 and 24