An event management company charges ₹4800 per guest, for a bulk booking for 100 guests. In addition, it offers a discount of ₹200 for each group of 10 guests over and above 100 guests booking. What is the number of guests that will maximize the amount of money the company receives on a booking? What is the maximum profit on such booking? |
Number of guests = 160, Maximum Profit = ₹5,60,000 Number of guests = 170, Maximum Profit = ₹5,78,000 Number of guests = 180, Maximum Profit = ₹5,76,000 Number of guests = 150, Maximum Profit = ₹5,40,000 |
Number of guests = 170, Maximum Profit = ₹5,78,000 |
The correct answer is Option (2) → Number of guests = 170, Maximum Profit = ₹5,78,000 Let the number of guests for the booking be x. Clearly, $x > 100$. According to given, profit $(P) = \left[4800-\frac{200}{10}(x - 100)\right] x$ $P=6800x-20x^2$ ...(i) Differentiating (i) w.r.t. x, we get $\frac{dP}{dx}=6800-40x$ and $\frac{d^2P}{dx^2}= -40$. Now, $\frac{dP}{dx}=0⇒ 6800-40x = 0⇒x=170$ $\frac{d^2P}{dx^2}=-40 <0$ $⇒ P$ is maximum at $x = 170$. Hence, a booking of 170 guests will maximize the profit and maximum profit $= 6800 × 170 - 20 × (170)^2 = ₹5,78,000$. |