Practicing Success
$\tan ^{-1}\left(\frac{\mathrm{x}}{\mathrm{y}}\right)-\tan ^{-1}\left(\frac{\mathrm{x}-\mathrm{y}}{\mathrm{x}+\mathrm{y}}\right)=$ |
\(\frac{π}{6}\) \(\frac{π}{3}\) \(\frac{π}{4}\) \(\frac{π}{2}\) |
\(\frac{π}{4}\) |
$tan^{-1}(\frac{x}{y})-tan^{-1}(\frac{\frac{x}{y}-1}{1+\frac{x}{y}})$ → Using property ⇒ $tan^{-1}a-tan^{-1}b=tan^{-1}(\frac{a-b}{1+ab})$ $tan^{-1}(\frac{x}{y})-tan^{-1}(\frac{x}{y})+tan^{-1}(1)⇒45°$ $tan^{-1}(1)=\frac{\pi}{4}$ |