In triangle ABC, if AB=BC and ∠B = 70°, ∠A will be:

According to the question,

AB = BC

Hence, ∠A=∠C

and ∠B = 70°

By angle sum property of triangle we know:

∠A+∠B+∠C = 180°

2∠A+∠B=180°

2∠A = 180-∠B = 180-70 = 110°

∠A  = \(\frac{ 110}{ 2}\)

∠A = 55°