ΔABC ∼ ΔDEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ΔDEF = 25 cm, then the perimeter of ΔABC is:

35 cm

We know that,

If triangles are similar then the ratio of the perimeter of triangles and corresponding sides are equal.

AB = 9.1 cm

DE = 6.5 cm

/(Perimeter of Δ DEF)  \(\frac{AB}{DE}\) = \(\frac{BC}{CF}\) = \(\frac{CA}{FD}\) = \(\frac{ Perimeter \; of \; Δ ABC }{ Perimeter \; of \; Δ DEF }\)

= \(\frac{9.1}{6.5}\) = \(\frac{ Perimeter \; of \; Δ ABC }{ 25 }\)

= Perimeter of Δ ABC = 35 cm