In the first 9 matches of a cricket tournament, the wickets taken by Jumpo are as follows:
3 2 0 1 3 0 5 1 4
Find the median of the number of wickets taken by Jumpo?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2
To find the median of the number of wickets taken by Jumpo, we follow these steps:
1. Arrange the Data in Ascending Order
The original data set is: 3, 2, 0, 1, 3, 0, 5, 1, 4
Sorting these numbers from smallest to largest:
0, 0, 1, 1, 2, 3, 3, 4, 5
2. Identify the Number of Observations ($n$)
There are 9 matches in total, so $n = 9$.
3. Determine the Position of the Median
Since $n$ is an odd number, the median is the middle term in the sorted list. The formula for the position is:
$\text{Median Position} = \frac{n + 1}{2}$
$\text{Median Position} = \frac{9 + 1}{2} = 5\text{th term}$
4. Locate the 5th Term
In the sorted list (0, 0, 1, 1, 2, 3, 3, 4, 5), the 5th term is 2.