The angular momentum of satellite
Answer & explanation
Correct answer: option 4
Given, r = 3.6 × 107 m, m = 5000 kg, v = 4000 m s–1, $\phi$ = 30°
Angular momentum of satellite L = mvr sin$\phi$
= 5000 × 4000 × 3.6 × 107 × sin 30°
= 3.6 × 1014 joule × second