In $\triangle \mathrm{ABC}$, right angled at $\mathrm{B}$, if $\cot \mathrm{A}=\frac{1}{2}$, then the value of $\frac{\sin A(\cos C+\cos A)}{\cos C(\sin C-\sin A)}$ is
Answer & explanation
Correct answer: option 2
A detailed explanation for this question is coming soon.