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The average of a set of 15 numbers is 41. Five numbers 21, 24, 39, 47 and 97 are removed from the above set. What will the average of the remaining 10 numbers? |
39.2 37.6 38.7 36.4 |
38.7 |
Sum of 15 numbers = 15 × 41 = 615 Sum of 5 numbers = 21 + 24 + 39 + 47 + 97 = 228 Remaining sum of 10 numbers = 615 - 228 = 387 Average = \(\frac{387}{10}\) = 38.7 |
