Practicing Success
Assuming that the silicon diode having resistance of 20 Ω, the current through the diode is (knee voltage 0.7 V) |
0 mA 10 mA 6.5 mA 13.5 mA |
6.5 mA |
Here diode is forward biased with voltage = 2 – 0 = 2V. $V_B = V_{knee} + IR$ 2 = 0.7 + I × 200 (∴ Total resistance = 180 + 20 = 200 Ω) $∴I=\frac{1.3}{200}=6.5mA$ |