Practicing Success
Practicing Success
CUET Preparation Today
The value of current in the adjoining diagram will be:
|
$0\, amp$ $10^{−2} amp$ $10^2\, amp$ $10^{−3} amp$ |
$10^{−2} amp$ |
$I_f=\frac{4-1}{300}=10^{-2}A$ |
