Match List-I with List-II.List-IList-II(i) Benzenesulphonyl chloride(…

The correct answer is Option (4) → (i)-(b), (ii)-(a), (iii)-(d), (iv)-(c)

(i) Benzenesulphonyl chloride — This matches (b) Hinsberg’s reagent. \( \ce{C6H5SO2Cl} \) reacts with primary and secondary amines to give sulphonamides and not with tertiary amines, so it is used to tell the three classes of amines apart.

(ii) Sulphanilic acid — This matches (a) Major product of the sulphonation of aniline. Aniline with concentrated \( \ce{H2SO4} \) gives anilinium hydrogensulphate, which on heating at 453–473 K gives p-aminobenzenesulphonic acid (sulphanilic acid).

(iii) Alkyldiazonium salts — This matches (d) Conversion to alcohols. Primary aliphatic amines with nitrous acid give alkyldiazonium salts, which are highly unstable and break down at once, giving nitrogen gas and an alcohol:

    \( \displaystyle \ce{R-NH2} \xrightarrow{\ce{NaNO2 + HCl}} \ce{[R-N2^+Cl^-]} \xrightarrow{\ce{H2O}} \ce{ROH + N2 + HCl} \)

(iv) Aryldiazonium salts — This matches (c) Dyes. Arenediazonium salts couple with phenols or aromatic amines to give azo compounds, which are coloured and are used as dyes.

NCERT (2026-27 edition):
9.6 Chemical Reactions – “… Benzenesulphonyl chloride (C₆H₅SO₂Cl), which is also known as Hinsberg’s reagent, reacts with primary and secondary amines to form sulphonamides.”
“(c) Sulphonation: Aniline reacts with concentrated sulphuric acid to form anilinium hydrogensulphate which on heating with sulphuric acid at 453-473K produces p-aminobenzene sulphonic acid, commonly known as sulphanilic acid, as the major product.”
“(a) Primary aliphatic amines react with nitrous acid to form aliphatic diazonium salts which being unstable, liberate nitrogen gas quantitatively and alcohols.”

Summary – “… Coupling reaction of aryldiazonium salts with phenols or arylamines give rise to the formation of azo dyes.”