A point charge 2 μC is located at the center of a cube of side 1.0 m. The net electric flux through the cube will be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( 2.26\times10^{5} \) Nm2/C
By Gauss’s law the total flux through any closed surface is the enclosed charge divided by \( \varepsilon_0 \); the size of the cube does not matter.
\( \displaystyle \phi = \frac{q}{\varepsilon_0} = \frac{2\times10^{-6}\,\mathrm{C}}{8.854\times10^{-12}\,\mathrm{C^{2}\,N^{-1}\,m^{-2}}} \)
\( \displaystyle \phi \approx 2.26\times10^{5}\,\mathrm{N\,m^{2}\,C^{-1}} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
