A current of I ampere flows through a resistance R when connected across a cell of emf E and internal resistance 1Ω. When R is increased by 50%, the current through the circuit is 0.8A. What is the value of R?
Answer & explanation
Correct answer: option 3
1.0 A = \(\frac{E}{1 \Omega+ R}\)
0.8 A = \(\frac{E}{1 \Omega + (R/3)}\)
R = 1 \(\Omega\)