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A current of I ampere flows through a resistance R when connected across a cell of emf E and internal resistance 1Ω. When R is increased by 50%, the current through the circuit is 0.8A. What is the value of R? |
4 Ω 6 Ω 1 Ω 2 Ω |
1 Ω |
1.0 A = \(\frac{E}{1 \Omega+ R}\) 0.8 A = \(\frac{E}{1 \Omega + (R/3)}\) R = 1 \(\Omega\)
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