As per Bohr's model the energy (in eV) required to remove electron from ground state of Li++ (doubly ionised lithium atom) is
Answer & explanation
Correct answer: option 4
$ E = 13.6\times \frac{Z^2}{n^2} = 13.6\times 3^2 = 122.4 eV$
As per Bohr's model the energy (in eV) required to remove electron from ground state of Li++ (doubly ionised lithium atom) is
Correct answer: option 4
$ E = 13.6\times \frac{Z^2}{n^2} = 13.6\times 3^2 = 122.4 eV$