The average of a set of 18 consecutive i

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Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Average

Question:

The average of a set of 18 consecutive integers is 22.5. What is the largest integer in the set ?

Options:

Correct Answer:

Explanation:

Let the 1st integer be x

18th integer = x + 17

Sum of 18 terms = \(\frac{18 × ( x + x + 17)}{2 × 18}\) = \(\frac{2x + 7}{2}\)

⇒ \(\frac{2x + 17}{2}\) = 22.5

⇒ x = 14

Largest number = x + 17 = 31