A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector?
Answer & explanation
Correct answer: option 3
Due to 10.2 eV photon one photon of energy 10.2 eV , an electron gets excited from n= 1 to n= 2 and when its come back to ground state it emits a photon of energy 10.2eV will be detected.
Due to 15 eV photon ( It is greater than binding energy of photon which is equal to 13.6eV)the electron will come out of the atom with energy = (15 - 13.6) = 1.4 eV.