In a right triangle for an acute angle x, find sinx. It is given that…

We are given that :-

tan x = \(\frac{5}{1}\)

{ we know, tan x = \(\frac{P}{B}\) }

By using pythagoras theorem,

P² + B² = H²

5² + 1² = H²

H = \(\sqrt {26 }\)

Now,

sin x

= \(\frac{P}{H}\)

= \(\frac{5}{√26}\)