Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

If Brewster's angle be 'θ', then the critical angle is

Options:

$\sin^{-1} (\cot θ)$

$(90-θ)$

$\sin^{-1} (\tan θ)$

$\frac{θ}{2}$

Correct Answer:

$\sin^{-1} (\cot θ)$

Explanation:

The correct answer is Option (1) → $\sin^{-1} (\cot θ)$