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CUET
Physics
Wave Optics
If Brewster's angle be 'θ', then the critical angle is
$\sin^{-1} (\cot θ)$
$(90-θ)$
$\sin^{-1} (\tan θ)$
$\frac{θ}{2}$
The correct answer is Option (1) → $\sin^{-1} (\cot θ)$